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Okezie Ikpeazu wins Abia governorship election [FULL RESULT]

Governor Okezie Ikpeazu of the Peoples Democratic Party, PDP, has been declared the winner of the 2019 gubernatorial election in Abia State.

Ikpeazu polled the total number of 261,127 to defeat Uche Ogah of the All Progressives Congress, APC, and Alex Otto of the All Progressives Grand Alliance, APGA.

He was declared winner by the INEC Returning Officer, Prof. Benjamin Ozumba.

“I hereby declare that Dr Okezie Ikpeazu, having satisfied all electoral requirements and scored the highest number of votes, is declared the winner and returned elected,” he declared.

The complete result as follows:

1.Obingwa APC…..3390 Apga….2679 PDP…..78803

2. Isialangwa south APC…..1569 Apga…5129 PDP…..19672

3. Isialangwa north APC…2404 Apga….2084 PDP…..19209

4. Arochukwu APC…..3819 Apga….8924 PDP… 5070

5. Ugwunagbo APC…1865 Apga….1054 PDP…..22084

6. Ikwuano APC….5619 Apga….1588 PDP…. 6286

7. Ukwa east APC……1447 Apga……1935 PDP….. 3819

8. Ukwa west APC…..3140 Apga….2270 PDP….11602

9. Umuahia south APC…7606 Apga….4502 PDP…8257

10. Osisioma APC….1981 Apga….2298 PDP….19835

11. Bende APC….12172 Apga….4238 PDP…7265

12. Isiukwuato APC….14146 Apga….1696 PDP…..3564

13. Umunneochi APC….7238 Apga….3190 PDP….. 7004

14. Ohaofia APC 6718 APGA 6883 PDP 19346

15. Aba South APC 5418 APGA 6802 PDP 5256

16. Abia North APC 4209 APGA 6216 PDP 8429

17. Umuahia North APC 16833 APGA 2878 PDP 15627

TOTAL VOTES;

Below is the total number of votes;

PDP – 261,127 APC – 99,574 APGA – 64,366

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